C语言 <ctype.h> ispunct() 函数

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  描述

  C库函数int ispunct(int c) 检查所传递的字符是否为标点字符。标点符号是不是字母数字的任何图形字符（如isgraph）（如isalnum）。
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  声明

  以下是ispunct()函数的声明。

  
  int ispunct(int c);
  

  参数

  • c - 这是要检查的字符。
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  返回值

  如果c是标点符号，则此函数返回非零值（true），否则返回零（false）。

  示例

  以下示例显示ispunct()函数的用法-

  
  #include <stdio.h>
  #include <ctype.h>
  
  int main () {
     int var1 = 't';
     int var2 = '1';
     int var3 = '/';
     int var4 = ' ';
  
     if( ispunct(var1) ) {
        printf("var1 = |%c| is a punctuation character\n", var1 );
     } else {
        printf("var1 = |%c| is not a punctuation character\n", var1 );
     }
     
     if( ispunct(var2) ) {
        printf("var2 = |%c| is a punctuation character\n", var2 );
     } else {
        printf("var2 = |%c| is not a punctuation character\n", var2 );
     }
     
     if( ispunct(var3) ) {
        printf("var3 = |%c| is a punctuation character\n", var3 );
     } else {
        printf("var3 = |%c| is not a punctuation character\n", var3 );
     }
     
     if( ispunct(var4) ) {
        printf("var4 = |%c| is a punctuation character\n", var4 );
     } else {
        printf("var4 = |%c| is not a punctuation character\n", var4 );
     }
     
     return(0);
  }  
  

  尝试一下

  让我们编译并运行上述程序，以产生以下结果-

  
  var1 = |t| is not a punctuation character
  var2 = |1| is not a punctuation character
  var3 = |/| is a punctuation character
  var4 = | | is not a punctuation character