Objective-C 指针传递给函数

  • 指针传递给函数

    Objective-C编程语言允许您将指针传递给函数。为此,只需将函数参数声明为指针类型。在一个简单的示例中,我们将一个无符号的长指针传递给一个函数,并更改该函数内部的值,该值会反映在调用函数中-
    
    #import <Foundation/Foundation.h>
    
    @interface SampleClass:NSObject
    - (void) getSeconds:(int *)par;
    @end
    
    @implementation SampleClass
    
    - (void) getSeconds:(int *)par {
     /* get the current number of seconds */
       *par = time( NULL );
       return;
    }
    
    @end
    
    int main () {
       int sec;
    
       SampleClass *sampleClass = [[SampleClass alloc]init];
       [sampleClass getSeconds:&sec];
    
       /* print the actual value */
       NSLog(@"Number of seconds: %d\n", sec );
    
       return 0;
    }
    
    
    2020-08-08 10:40:03.005 test[11928:4136] Number of seconds: 1596854402
    
    该函数可以接受一个指针,也可以接受一个数组,如以下示例所示:
    
    @interface SampleClass:NSObject
    /* function declaration */
    - (double) getAverage:(int *)arr ofSize:(int) size;
    @end
    
    @implementation SampleClass
    
    - (double) getAverage:(int *)arr ofSize:(int) size {
       int    i, sum = 0;       
       double avg;
    
       for (i = 0; i < size; ++i) {
          sum += arr[i];
       }
    
       avg = (double)sum / size;
       return avg;
    }
    
    @end
    
    int main () {
    
       /* an int array with 5 elements */
       int balance[5] = {1000, 2, 3, 17, 50};
       double avg;
    
       SampleClass *sampleClass = [[SampleClass alloc]init];
       /* pass pointer to the array as an argument */
       avg = [sampleClass getAverage: balance ofSize: 5 ] ;
    
       /* output the returned value  */
       NSLog(@"Average value is: %f\n", avg );
    
       return 0;
    }
    
    
    2020-08-08 10:42:37.483 test[6612:332] Average value is: 214.400000